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4x^2+66x-90=0
a = 4; b = 66; c = -90;
Δ = b2-4ac
Δ = 662-4·4·(-90)
Δ = 5796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5796}=\sqrt{36*161}=\sqrt{36}*\sqrt{161}=6\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-6\sqrt{161}}{2*4}=\frac{-66-6\sqrt{161}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+6\sqrt{161}}{2*4}=\frac{-66+6\sqrt{161}}{8} $
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